Given H = x2 + 8, H-1 =????
2006-10-12 13:34:58 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
H = x^2 + 8
x = (H^-1)^2 + 8
x - 8 = (H^-1)^2
H^-1 = sqrt(x - 8)
By the way, don't work out the (H^-1)^2 to be H^(-2), because you are trying to find H^-1 not H^-2
2006-10-12 15:41:35 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
H = x^2 + 8
H-1 =x^2+8-1+x^2+7
2006-10-12 22:16:43 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
H = x^2+8
H-1 = ????
Substitue
x^2+8-1 = x^2+7
2006-10-12 20:37:22 · answer #3 · answered by danjlil_43515 4 · 0⤊ 0⤋
x^2+7
2006-10-12 20:50:00 · answer #4 · answered by raj 7 · 0⤊ 0⤋
value of H in terms of x is x2+8
H-1=x2+8-1
H-1=x2+7
2006-10-12 20:38:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x2 + 7
2006-10-12 20:37:32 · answer #6 · answered by Alan Turing 5 · 0⤊ 0⤋
H = 2x +8
H-1 = (2x+8) - 1
The final answer is 2x - 7.
2006-10-12 20:41:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋