a quanity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of the gas is raised to 533 degrees kelvin, what is the new volume of the gas?
2006-10-12 13:26:46 · 3 answers · asked by kay_267 2 in Science & Mathematics ➔ Physics
If external pressure remains unchanged then you can use the formula V1/T1=V2/T2 to get the result, where V1=0.2 m^3, T1=333 K, T2=533 K.
But if the pressure changes as well then there is not enough input in the question to get an answer.
2006-10-13 10:50:48 · answer #1 · answered by fanis t 2 · 0⤊ 1⤋
PV(a million)=nRT(a million) PV(2)=nRT(2) Divide equation 2 via equation a million, and you get: V(2)/V(a million)=T(2)/T(a million) sparkling up for V(2), which equals T(2)V(a million)/T(a million), which may be: 533 ok * 0.20 m3 / 333 ok that's 0.32 m3.
2016-12-13 07:16:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
PV = nRT
so if P is constant, n is constant and R is a constant
V1/T1 = V2/T2 => V2 = V1*T2/T1 = 0.32 cu m
2006-10-12 13:38:48 · answer #3 · answered by feanor 7 · 0⤊ 0⤋