Physics homework help!!! PLEASE HELP!?

Question

Ok i have 3 questions from physics and i dont understand any of them. Could you please explain how to do it and give me the answer? I will give u best answer and my eternal gratitude!!! The questions are as follow:

1. A kid fires a slingshot pellet directly at a target that is far enough away to talk one-half-second to reach. How far below does the target hit? How high above should he aim? ( he is throwing a distance of 60meters standing on a platform 20meters high)...

2. The boy on the platform throws a ball a distance of 60 meters, as mentioned in number 1, at what speed is the ball thrown (in meters/second)?

3. A shiny new sports car sits in a parking lot of a car dealership. Above is a cargo plane flying horizontally at 50 m/s. At the exact moment the plane is 125 meters directly above the car, a heavy crate accidentaly falls from its cargo doors. Realative to the car, where will the crate hit? ( speed of gravity if needed can be rounded to 10m/s.)

Answer 1

1.) Since you're not concerned with horizontal distance, you only need 1 formula: d = vt + 1/2at^2.
Before the shot is fired, v = 0, so the equation becomes d = 1/2 at^2. a = 9.8 m/s^2 (gravity), so:
d = .5 * 9.8 * t^2
d = 4.9 (.5)^2 = 1.225 m. The pellet will have dropped 1.225m when it reaches the target.

2.) If the boy throws a ball 60 meters in .5 seconds, then v = d/t = 120 m/s.

3.) This combines the concepts in 1 and 2. After being dropped, imagine 2 things happening to the crate:
a.) it drops with an acceleration of 10 m/s^2
b.) it moves away from the car at 50 m/s

You already know the height, the velocity, and the acceleration. Using a, find the time, then plug the time into b to determine how far away from the car the crate lands.

a.) d = vt + 1/2 at^2. v = 0, so d = 1/2 at^2
125 = .5 * 10 * t^2
t^2 = 25
t = 5

b.) d = vt
d = 50 m/s * 5 s
d = 250 m away from the car (solution).

Answer 2

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Answer 3

1) 3 in
2)53 mps
so cant help u on 3