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how much current flows through the component?

2006-10-12 13:04:32 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

E= IR, therefore I=E/R or 120/46=approx 26.1 amps

2006-10-12 13:15:52 · answer #1 · answered by WC 7 · 0 0

Consider 46 Ω as pure resistance the current would be
I = 120/46 = 2.61 Amperes

2006-10-14 02:06:52 · answer #2 · answered by dwarf 3 · 0 0

120/46 is 26.1? Must have gone to the Al Sharpton shcool of math.

2006-10-13 17:46:17 · answer #3 · answered by Nomadd 7 · 0 0

I= (V/R)

2006-10-12 20:11:59 · answer #4 · answered by revicamc 4 · 0 0

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