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I have no idea how to do this. i have a whole page of notes on it but i still dont get it.
i need to create formulas to the following:
1)barium chloride and ammonium carbonate
2)barium chloride and ammonium phosphate
3)calcium chloride and ammonium carbonate
4)calcium chloride and ammonium phosphate
5)strontium chloride and ammonium carbonate
6)strontium chloride and ammonium phosphate

i was told to:
a)find the symbols
b)find the oxidation states
c)criss cross and drop signs
d)reduce
but i dont understand...??? please help me, and possibly give me the answers but show me how you got them

2006-10-12 12:49:46 · 5 answers · asked by um yea hi 4 in Science & Mathematics Chemistry

5 answers

Fatima, you also have to criss cross... so you're partially correct

ok, using the periodic table, it gives you the symbols, and it also gives you the oxidation state. To find the oxidation states, it follows as this, H, Li, Na, and the rest of the column has an oxidation state of +1, the column of Be,Mg, Ca, has oxidation state of +2, the column of B, Al, Ga, is +3, the column of C,Si, and Ge, can be +4 or -4 and the column of P, N, As, has -3, O, S, Se are -2, and finally, F, Cl, Br = -1

Symbols just go onto a periodic table... Carbonate is CO3 (2-), chloride (2-), Phosphate PO4 (3-), ammonium NH4 (3+)

To criss cross, it means to do it this way:

Barium carbonate and Ammonium Chloride (you then need to balance it)
3BaCl2 + (NH4)2 (CO3)3 = 3Ba(CO3) + (NH4)2 (Cl2)3
Barium Phosphate and Ammonium Chloride
3BaCl2 + 2NH4PO4 = (Ba)3(PO4)2 + (NH4)2 (Cl2)3
Calcium Carbonate and Ammonium Chloride
3CaCl2 + (NH4)2 (CO3)3 = Ca3(CO3)3 + (NH4)2 (Cl2)3

try the rest on your own...
Calcium Phosphate and Ammonium Chloride
strontium carbonate and Ammonium Chloride
and strontium phosphate and Ammonium Chloride

alan turing... then u have it unbalanced
BaCl2 + (NH4)2^6+ CO3^2- --> BaCO3 + 2NH4^6+Cl^2- because the charge of CO3 is 2- and (NH4)2 with a charge of 6+ and -2 charge on the right side too...unbalanced...

2006-10-12 13:01:33 · answer #1 · answered by ryanprague1 5 · 0 0

ok i can help you with only few just to give you an idea but you can follow the rest. for barium chloride symbol is Ba for barium and Cl for chlorine oxidation states are Ba2+ and Cl- bring them together ie Ba2+ Cl- and criss cross now when you criss cross you get BaCl2
and for ammonium carbonate ammonium is NH4+ and Carbonate is CO3 with charge2- which will become (NH4)2CO3

2006-10-12 13:00:16 · answer #2 · answered by rohit 2 · 0 0

In word you will have something call the Symbol function. Go to the top menu and then Insert -> Symbol Now you can choose a host of symbols (both scientific and otherwise) to depict your formulas. Hope this helps. Good luck!

2016-03-28 06:56:18 · answer #3 · answered by Marie 4 · 0 0

Ryan is wrong in his balancing. He wrote,

"3BaCl2 + (NH4)2 (CO3)3 = Ba3(CO3)3 + (NH4)2 (Cl2)3"

He should have written:

"BaCl2 + (NH4)2CO3 --> BaCO3 + 2NH4Cl"

He made it more difficult than it needed to be.

2006-10-12 13:25:23 · answer #4 · answered by Alan Turing 5 · 0 1

1) BaCl2 (NH4)2CO3
2)BaCl2 (NH4)3PO4
3) CaCl2 (NH4)2CO3
4) CaCl2 (NH4)3PO4
5) SrCl2 (NH4)CO3
6) SrCl2 (NH4)3PO4

These are final answers.

2006-10-12 13:00:44 · answer #5 · answered by Fatima A 3 · 0 1

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