Fatima, you also have to criss cross... so you're partially correct
ok, using the periodic table, it gives you the symbols, and it also gives you the oxidation state. To find the oxidation states, it follows as this, H, Li, Na, and the rest of the column has an oxidation state of +1, the column of Be,Mg, Ca, has oxidation state of +2, the column of B, Al, Ga, is +3, the column of C,Si, and Ge, can be +4 or -4 and the column of P, N, As, has -3, O, S, Se are -2, and finally, F, Cl, Br = -1
Symbols just go onto a periodic table... Carbonate is CO3 (2-), chloride (2-), Phosphate PO4 (3-), ammonium NH4 (3+)
To criss cross, it means to do it this way:
Barium carbonate and Ammonium Chloride (you then need to balance it)
3BaCl2 + (NH4)2 (CO3)3 = 3Ba(CO3) + (NH4)2 (Cl2)3
Barium Phosphate and Ammonium Chloride
3BaCl2 + 2NH4PO4 = (Ba)3(PO4)2 + (NH4)2 (Cl2)3
Calcium Carbonate and Ammonium Chloride
3CaCl2 + (NH4)2 (CO3)3 = Ca3(CO3)3 + (NH4)2 (Cl2)3
try the rest on your own...
Calcium Phosphate and Ammonium Chloride
strontium carbonate and Ammonium Chloride
and strontium phosphate and Ammonium Chloride
alan turing... then u have it unbalanced
BaCl2 + (NH4)2^6+ CO3^2- --> BaCO3 + 2NH4^6+Cl^2- because the charge of CO3 is 2- and (NH4)2 with a charge of 6+ and -2 charge on the right side too...unbalanced...
2006-10-12 13:01:33
·
answer #1
·
answered by ryanprague1 5
·
0⤊
0⤋
ok i can help you with only few just to give you an idea but you can follow the rest. for barium chloride symbol is Ba for barium and Cl for chlorine oxidation states are Ba2+ and Cl- bring them together ie Ba2+ Cl- and criss cross now when you criss cross you get BaCl2
and for ammonium carbonate ammonium is NH4+ and Carbonate is CO3 with charge2- which will become (NH4)2CO3
2006-10-12 13:00:16
·
answer #2
·
answered by rohit 2
·
0⤊
0⤋
In word you will have something call the Symbol function. Go to the top menu and then Insert -> Symbol Now you can choose a host of symbols (both scientific and otherwise) to depict your formulas. Hope this helps. Good luck!
2016-03-28 06:56:18
·
answer #3
·
answered by Marie 4
·
0⤊
0⤋
Ryan is wrong in his balancing. He wrote,
"3BaCl2 + (NH4)2 (CO3)3 = Ba3(CO3)3 + (NH4)2 (Cl2)3"
He should have written:
"BaCl2 + (NH4)2CO3 --> BaCO3 + 2NH4Cl"
He made it more difficult than it needed to be.
2006-10-12 13:25:23
·
answer #4
·
answered by Alan Turing 5
·
0⤊
1⤋
1) BaCl2 (NH4)2CO3
2)BaCl2 (NH4)3PO4
3) CaCl2 (NH4)2CO3
4) CaCl2 (NH4)3PO4
5) SrCl2 (NH4)CO3
6) SrCl2 (NH4)3PO4
These are final answers.
2006-10-12 13:00:44
·
answer #5
·
answered by Fatima A 3
·
0⤊
1⤋