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[3a^2/5]^-3

The [ ] are positive exponents

2006-10-12 12:40:45 · 3 answers · asked by britiani j 1 in Science & Mathematics ➔ Mathematics

3 answers

125/3^3a^6
(125/27)(1/a^6)

2006-10-12 12:45:32 · answer #1 · answered by raj 7 · 0⤊ 0⤋

you have to distribute the -3 within the [ ] to each

3^-3 * (a^2\5)^-3

distribute the -3 to the second part by multipling
3^-3 * a^-6\5 .....negative exponents force numbers to under a division sign changing the exponents to positives

1/3^3*a^6/5

so....1/ 27a^(6/5)

2006-10-12 19:47:19 · answer #2 · answered by travislizzie 2 · 0⤊ 0⤋

Invert the quantity within the bracket to remove the negative exponent.

125/27a^6

2006-10-12 20:12:48 · answer #3 · answered by davidosterberg1 6 · 0⤊ 0⤋