2006-10-12 11:40:43 · 6 answers · asked by mrkkerekes 1 in Education & Reference ➔ Trivia
1,000,000,000,000 1 trillion including zero.
2006-10-12 11:44:29 · answer #1 · answered by Barkley Hound 7 · 0⤊ 0⤋
There are (9)(10^11) 12 digit numbers.
Start by asking how many 2 digit numbers there are.
Well, there are 10 digits so you have 10 possibilities for the first digit and 10 possibilities for the second digit.
10x 10=100 right? Not quite.
You cannot have 0 as the first digit, so there are only 9 choices for the first digit or 90, two digit numbers.
This makes sense. The 90 numbers with 2 digits are just the integers from 10-99.
For 3 digits, there are 900 (9)(10)(10)=900.
Again, these are just the integers from 100-999.
So for 12 digit numbers there are (9)(10^11) combinations.
Some people are saying that there are (10^12) -1 numbers, but this is not right. That is the total of all of the numbers from 1 to 10^12, but it includes 1 digit, 2 digit , 3 digit.....all the way up to 11 digit numbers as well. You asked for only the twelve digit numbers.
2006-10-12 11:59:55 · answer #2 · answered by True Blue 6 · 0⤊ 0⤋
12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1... = possible combination
2006-10-12 14:08:06 · answer #3 · answered by amber 3 · 0⤊ 0⤋
999,999,999,999 combinations (one short of one trillion)
2006-10-12 11:43:26 · answer #4 · answered by Madkins007 7 · 0⤊ 0⤋
12! is your answer
12! = 12x11x10x9x8x7x6x5x4x3x2x1
2006-10-12 11:42:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋
999999999999
2006-10-14 20:12:24 · answer #6 · answered by ash 1 · 0⤊ 0⤋