1: Find the lateral area of a rectangular prism 5 feet wide, 15 feet long, and 10 feet high.
2: Find the lateral area of a cube with each edge 3.4 inches.
3: Find the lateral area of a triangular prism 12.5 feet high and edges 3.4 feet, 4.5 feet, and 5.6 feet.
4 Find the lateral area of a cylinder with radius 4.7 inches and altitude 20.3 inches.
:5 Find the lateral area of a cone with radius 3 inches, altitude 4 inches, and slant height 5 inches.
6: Find the surface area of a baseball with diameter 3 inches
7: Find the volujme of a piece of lumber 4" x 6" x 24'.
8: Find the volume of a rectangular prism 8.5' X 13.6' X 9.5'.
9: Find the volume of a cylindrical can 2.5" in radius and 6" tall
2006-10-12 10:40:16 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Ok you dumb assholes. If you don't plan on answer the question don't click the link . Oh and yeah I am lazy. So stop being a stupid ***** please.
2006-10-12 11:12:28 · update #1
Sweetpea, you're sooooo lazy,
you can't even bother to type 'please'.
and when you fail math, you'll blame the teacher.
2006-10-12 10:48:06 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
1. I'm not sure what is meant by "lateral area": The term is new to me. I'm assuming it means the area of all six surfaces, but if in fact it only means the sides, leaving out the top and bottom, then leave out the 5x15 part of my solution:
There are six rectangular surfaces: two of them are each 5 ft by 15 ft, making their area 75 sq ft each, 150 sq ft total. Another two are 5 ft by 10 ft, making 100 sq ft total, and the other two are 15 ft by 10 ft making 300 sq ft total. Altogether 150 + 100 + 300 sq ft. There is a formula for this: Area = 2x(ab + bc + ca)
2. basically the same but all sides are equal so it should be easier.
3. The areas of the three sloping triangular sides can be found using 0.5xbasexheight, but working out the heights of those triangles would be quite difficult, and I haven't done it. Using 12.5 as the height of each gives results which are too small, but all of the correct heights would be less than 12.65, so the error won't be too great. Maybe 12.6 ft would be a good rough guess.
So work out 0.5x12.6x each of 3.4, 4.5, and 5.6, and add them together. If "lateral area" means just the sides, this is the result. If you're supposed to include the base, then you need to use the formula
Area = sqrt( s(s-a)(s-b)(s-c)), where a, b, and c are the sides of the triangle (i.e. 3.4, 4.5, and 5.6 in this case), and to work out s you have to add the three sides together and halve the result. (Do it. You should get 6.75 as the value for s) I think the area of this bottom triangle comes to about 7.6 sq inches, but that's just a rough calculation in my head and I may have made a big blunder!
4. The formula for the curved part is 2 x pi x r x h, which is about 600 (you work it out accurately!). If you have to include the top and bottom, each of them is pi x (4.7^2), about 69? All up, about 740 sq inches. If you like you can email to me the accurate result at h_chalker@yahoo.com.au
5. The formula for the sloping part is pi x r x slant height, which is about 47 sq inches I think. Adding the base pi x r^2, about 28, gives a total of about 75 sq inches.
6. The formula is 4 x pi x r^2, and since r is 1.5 (half the diameter), this should come to about 28 sq inches.
7. Formula for volume is length x breadth x height, but the trick here is that the units are different. You can use 288" for the length and give the answer in cubic inches, or else leave it as 24 and then use "half" and "one third" for the other two (sorry I can't type fractions here, and I'm not using decimals because one third in decimal form is repeating), and get the answer in cubic ft.
8. Come on, you can do this one yourself. Same formula as 7. and no tricks with units!
9. Formula is (area of base) x (height), and since the base is a circle, that will be pi x 2.5^2 x 6, about 116 cubic inches I think.
So I haven't completed the working for any of them, and that means you can still do it conscientiously and say you've done your own homework. Otherwise it's useless.
2006-10-12 11:26:12 · answer #2 · answered by Hy 7 · 1⤊ 0⤋
Check out the formula given in the following link! It should help you get started. Yahoo Answers is not a place asking others to do your own work.
2006-10-12 10:48:17 · answer #3 · answered by Isaac 2 · 0⤊ 0⤋
There is a difference between getting some help with homework and having it all done for you.
But you can look up the formulas and go from there.
2006-10-12 10:46:29 · answer #4 · answered by vabanu 2 · 0⤊ 0⤋
To find the volume of something multiply the widthxheightxlength. You need to do this on # 7,8
Email me at: manateeluver32@yahoo.com if you have anymore questions.
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2006-10-12 10:52:52 · answer #5 · answered by manateeluver32 3 · 0⤊ 0⤋
whoaaaaaaaaaaaaaaaaaa!!! sweetpea you askin for a lil too much at one time but just email me at ashleypooh013@yahoo.com and ask me ant question you would like but one at a time please! and ill surley give you some help!! cause im just nice like that!!!!
2006-10-12 11:06:54 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I've already graduated!! You should be able to complete your own homework!!
2006-10-12 10:45:06 · answer #7 · answered by kane_rosebud 2 · 0⤊ 1⤋
dont know math
look for a math tutor.
that can help.
hahahhahah
2006-10-12 10:41:34 · answer #8 · answered by laura_jamela 2 · 0⤊ 1⤋
who cares
2006-10-12 10:46:01 · answer #9 · answered by kukamongakid 3 · 0⤊ 1⤋
r u telling us to do it???
2006-10-12 10:47:44 · answer #10 · answered by bronx CHICA 2 · 0⤊ 0⤋