What would the algebraic and interval notations be for
|2x + 5| >= 7
My answer: (-infinity, 4) U (4, + infinity) for interval notation
(4, -4) for alg. int
2006-10-12 10:19:15 · 7 answers · asked by Kendall 1 in Science & Mathematics ➔ Mathematics
We have
2x + 5 >= 7 or 2x + 5 <= -7
Subtract 5 from each side
2x >= 2 or 2x <= -12
Divide both sides by 2
x >= 1 or x <= -6
Interval notation: (-infinity, -6] U [1, +infinity)
Note: Since it is greater than or equal to you need to use brackets.
2006-10-12 10:33:30 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
2x+5>=7 ~take five from each side
-5 -5 ~then u get 2x>=2
2x>=2 ~then divide each side by 2
2/2x>=2/2 ~then x is = to 1
x>=1
2006-10-12 18:25:38 · answer #2 · answered by janet h 1 · 0⤊ 1⤋
x<= -6 U x>= 1/2 is my pick.
2006-10-12 17:31:39 · answer #3 · answered by daedgewood 4 · 0⤊ 1⤋
x= 1
2(1) +5>=7
Are you talking about absolute value?
2006-10-12 17:30:27 · answer #4 · answered by mamicolao@sbcglobal.net 1 · 0⤊ 1⤋
-6, 1
2006-10-12 17:52:40 · answer #5 · answered by FacingEviction 4 · 0⤊ 1⤋
the invalid range is from -6 to 1, exclusive
2006-10-12 17:30:47 · answer #6 · answered by feanor 7 · 0⤊ 1⤋
do ur own homework
2006-10-12 17:33:07 · answer #7 · answered by S A 3 · 0⤊ 1⤋