Help with this math problem?

Question

Z=P-kP

I'm confused on how to do a problem like this. I'm supposed to find out how to find out what P is.

An easier problem I understanded is:
A=1/2*j*m
2A/j =m

Can anybody help me with the first problem?

Explain it please!!

Answer 1

well if Z and kP are given (and kP is just one term) then P = Z+kP

Z=P-kP is the original problem
Add kP to both sides of the problem yeilds:
Z + kP = P - kP + kP

and then simplify the right side because the (-kP + kP) cancels each other and you're left with
Z + kP = P

if however kP is meant to be two seperate terms "k" and "P", then it is a different answer which you can see the answer below

Z = P -kP

then Z = P (1-k)

divide each side by (1-k) and get solution of

P=Z/(1-k)

Answer 2

P = Z/(1-k)

Answer 3

What you want to do is get p all by itself.
So... On the side that has P-kP factor out the P so you are left with Z=P(1-k). Because when you multiply the P back into (1-k) you get the orginal P-kP, P(1-k)=P-kP.

Then once P is factores out divide by the (1-k) on both sides...

Z/(1-k)=P(1-K)/(1-k)

The (1-K) cancels out on the right. SO you are left with...

P=Z/(1-K)

Answer 4

All you have to do is collect the P's together and divide by the rest so you have P on one side only.

Z = P - kP = P(1-k) if you multiply P by 1 and then by -k you get your original P - kP

The last part is to divide both sides by (1-k) and you end up with
Z/(1-k) = P

Answer 5

Z=P-kP
Z=P(1-k)
P=Z/(1-k)

Answer 6

The easier problem you understand doesn't use the "distributive law", which the other one does:

Z = P - k*P
Z = 1*P - k*P
Z = (1 - k) * P <========
Z / (1 - k) = P
P = Z / (1 - k)

The "distributive law" was used to get to the line with the arrow.

Answer 7

Start with: Z=P(1-k)
then: P=Z/(1-k)

OK