O.k. You see your friend Jessica and she has a bag with 100 pices of candy.You See you friend Lilly She has a bag with 624 pices of candy. You have a bag with 6,895 pices of candy.Your mom gives you and all your friends 543 pices of candy each. How many pices of candy do you and all your friends together?
2006-10-12 09:39:32 · 19 answers · asked by big brat 1 in Science & Mathematics ➔ Mathematics
If you add up the total amount of how each person has; which comes to a total amount of 7,619. Than multiply 543 by 3 which gives you 1,629. Than add 7,619 and 1,629; which gives you a total of 9248. If you'd like a little more detail or instructions on how to figure these problems out please do not hesitate to ask.
2006-10-12 09:42:28 · answer #1 · answered by glenn s 2 · 2⤊ 0⤋
100 + 624 + 6895 + 543 + 543 + 543 = 9248
2006-10-12 16:41:03 · answer #2 · answered by MsMath 7 · 2⤊ 0⤋
(3)(543) + 100 + 624 + 6895 = 9248 pieces of candie.
2006-10-12 16:46:21 · answer #3 · answered by Danny B 3 · 1⤊ 0⤋
the problem would be like this even though there are two different ways
100+624+6,895+543(3)=9,248
or you can do it like this
100+624+6,895+543+543+543=9,248
either way you get the same answer
2006-10-12 17:02:04 · answer #4 · answered by ♥KiYa♥ 3 · 0⤊ 0⤋
Jessica: 100+543=643 pieces
Lilly: 684+543=1227 pieces
You: 6895+543=7438 pieces
Total 9308 peices
You will also have HUGE tummy aches!
2006-10-12 16:58:24 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
total no. of candy
=100+624+6895+3*543
=9248
2006-10-12 16:45:02 · answer #6 · answered by openpsychy 6 · 1⤊ 0⤋
(3*543)+100+624+6895 =9248
2006-10-12 16:42:13 · answer #7 · answered by ? 7 · 2⤊ 0⤋
100 + 624 + 6,895 + 7,619
543 x 3 =1,629
7,619 + 1,629 = 9,248
.
2006-10-12 16:49:47 · answer #8 · answered by ? ? ? bloody_angel ??? 3 · 0⤊ 0⤋
(100 + 543) + (624 + 543) + (6895 + 543) = 9248
Therefore you will have 9248 pieces of candy all together
^_^
2006-10-12 16:41:43 · answer #9 · answered by Mariko 4 · 1⤊ 2⤋
100+624+6895+3*543 (Ithink)
2006-10-12 16:42:58 · answer #10 · answered by Dr. J. 6 · 2⤊ 0⤋