One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
2006-10-12 09:00:23 · 5 answers · asked by Nikitty 2 in Science & Mathematics ➔ Mathematics
*rate of 44 mi/h.
missed that part!
2006-10-12 09:04:27 · update #1
Without the speed of the 1st bus, 2 + any number
44t + 48(t-1) = 274
92t = 322
t = 3.5
T = 4:30
2006-10-12 09:05:24 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
the second bus will join the first bus 12 hours later and be 274 mi apart 68.5 hours later.
Impossible due to gas restrictions.
2006-10-12 09:11:42 · answer #2 · answered by Diego D 1 · 0⤊ 1⤋
You lost some information in writing the question. You need to know the average rate of the first bus and I'm not seeing it.
2006-10-12 09:02:42 · answer #3 · answered by SmileyGirl 4 · 0⤊ 1⤋
44 + 44x + 48x = 274
92x = 230
x = 2.5
Add this to the starting time of the second bus, and you have:
4:30PM
2006-10-12 09:10:59 · answer #4 · answered by warmspirited 3 · 1⤊ 0⤋
when the 2nd bus reaches Cincinatti
2006-10-12 09:04:38 · answer #5 · answered by Dale S 2 · 0⤊ 1⤋