Math 2 need help.?

Question

16x + 15y - 477
9x - 4y = -167

i ment = 477 not - 477

Answer 1

If the equation is 16x+15y=477 and 9x-4y=-167 then the solution is as below:-

Let us say
16x+15y= 477 ---------------------(1)
9x-4y= -167 ----------------------(2)

multiply equation , (1) by -4 and (2) by +15 (cross multiplication to cancel one variable), we get

(1) x -4 ------ - 64x-60y= -1908
(2) x 15 ----- 135x-60y=-2505

subtract (1)-(2) we get,

-199x = 597
x = 597/-199
x= -3

Substitute the value of x in equ. (2) to find the value of Y

(2) -------- 9x-4y=-167
9(-3)-4y=-167
-27-4y=-167
-4y = -167+27
-4y = -140
y = -140/-4
y = 35

Verify the value of x and y in equ (1)

x=-3, y=35

(1) ---- 16x+15(35)= 477
16(-3)+525=477
-48+525=477
477 = 477
LHS = RHS

SO OUR SOLUTION TO VARIABLE X AND Y ARE CORRECT.
LET ME KNOW WHETHER YOU ARE HAPPY WITH THE ANSWER.

JACK

Answer 2

If your equations are like these:
(1) 16x + 15y = 477
(2) 9x - 4y = -167
Then add (1) and (2)
(3) 25x + 11y = 310
(4) x = [(310 - 11y)] / 25
Substitute (4) in (1):
(5) [(16) (310-11y)] / [25] + 15Y = 477
(6) (16)(310) - (16)(11)(y) + (25)(15)y = (477)(25)
y = 35
Substitute: y = 35 in (1)
(7) 16x + (15)(35) = 477
16x = 477 - (15)(35)
x = -3
Check (A):
Use equation (1)
(16)(-3) + (15)(35) = 477
-48 + 525 = 477
477 = 477
Check (B):
Use equation (2)
(9)(-3) -(4)(35) = -167
-27 - 140 = - 167
-167 = -167

Answer 3

4(16x+15y=477)
15(9x-4y=-167)
simply

64x+60y=1980
135x-60y=-2505

199x =-525


X= -525 /199 = 2.64


Putting the value of x in the equation will give

Y=46.94

That’s all u have the value of x and y

Answer 4

I think the person who gave you this problem needs help from a shrink.. Anyone who gives student a problem like this aught to spend a fortnight in Pillory.
There are four common methods for solving simultaneous Linear Equations.

Addition
Subtraction These two only when one of the unknowns can be eliminated by either method,
such as -2 X and +2X which when added
eliminates one unknown

Substitution: Number the Equations 1 and 2.
Solve one of the equations for one of the Unknowns
and substitute the result into the other equation and solve for the remaining unknown.

Comparison, wherein one Equation is compared to the other. You solve both equations for one of the unknowns and then cross multiply to compare one to the other and substitute the solved for value back into one of the equations and solve for the other.

I would recommend that you use substitution and a good scientific calculator to solve this problem.

Be careful of required sign changes when transposing any factors or Terms.

Answer 5

there is a mistake in first equation, "=" sign is missing.
multiply these equations with such numbers so that co-efficients of x or y may become equal then eiether x or y will cancel and value of other will be obtained . after getting value of x or y put it in anyequation given here to find value of others.
this type of questions are called simultaneous equations in two variables.

Answer 6

Pi times the squre root of blah I know the anwser but will I tell you maybe Go time. 24x+30y=643

Answer 7

The first U can't simplify anymore, same with second!

Answer 8

the equations haven't been presented properly