A ->->-> B
A cyclist travels from A to B. At A she is travelling at 8m/s. She descends a vertical distance of 20m to the bottom of the hill from A. The road eventually rises 12m vertically to B. At B she is travelling at 5m/s. She and the bike have a mass of 80 kg. The total distance along the road from A to B is 500m. There is a constant resistance of 20N. What is the work done from A to B? At B the road is horizontal. She is accelerating at 0.5m/s/s. What is the power generated by her at B?
2006-10-12 07:51:47 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Love to help you but your question and its details are very muddled. Is this the actual wording of a question you have been set?
2006-10-12 19:10:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Why is this a mechanics problem? Power generated is 7 bhp per millisecond, providing the wind is behind her, and she is ringing her bell to clear the route ahead.
2006-10-12 15:02:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a)
dW = F(dot)ds
W = 20*500 -80*9.8*(20-12) Nm
(change signs for work done ON the bike&rider)
b)
P = (80*0.5 + 20)*5 Nm/s
2006-10-12 15:21:51 · answer #3 · answered by Helmut 7 · 1⤊ 0⤋
Your questionn not clear. At one point you say at B she travelling at 5m/sec. In the same breath you say at B she is accelerating at .5/m/sec^2.Which one is true? she is travelling at uniform rate or accelerating?
2006-10-12 15:38:01 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
Do your own homework :>
2006-10-12 14:59:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
tell it much clearly
2006-10-12 14:56:01 · answer #6 · answered by Sai♥Pranav 3 · 0⤊ 0⤋