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2006-10-12 07:17:14 · 10 answers · asked by bobbysgirlmeri 2 in Education & Reference Homework Help

10 answers

8a-4b-3a+6b=5a+2b

2006-10-12 07:20:18 · answer #1 · answered by raj 7 · 0 0

No, just use distributive property.

FOIL is when you have something like (x-a)(x+c).

Just take the 4 and multiply it by the (2a-b). Then take the 3 and multiply it by the (a-2b). Then combine like terms.

4(2a-b) - 3(a-2b) =

8a - 4b - 3a +6b =

5a + 2b

Hope that helps! :-)

2006-10-12 14:19:19 · answer #2 · answered by I ♥ AUG 6 · 0 0

Not exactly. The FOIL method is used to multiply two polynomials. The second polynomial is being subtracted from the first.
4(2a-b)-3(a-2b)
(8a-4b)-(3a-6b)
(8a-3a)+(-4b+6b)
5a+2b

2006-10-12 14:22:31 · answer #3 · answered by ? 6 · 0 0

This problem is a distributive problem so you would multiply 2a-b times 4 and then multiply a-2b times -3. Once you have those terms multiplied out add your like terms.

FOIL works when you are multiplying a binomial times a binomial, such as (x-3)(2x+5).

Hope this helps. Good Luck.

2006-10-12 14:20:34 · answer #4 · answered by SmileyGirl 4 · 0 0

No.

4(2a-b) -3(a-2b)
8a-4b-3a+6b
5a+2b

2006-10-12 15:13:55 · answer #5 · answered by dad_grl04 1 · 0 0

FOIL is used for multiplying. Here's the answer, not using FOIL:

4(2a-b)-3(a-2b)

(8a-4b)-(3a-6b)

8a-4b-3a+6b

5a+2b

2006-10-12 14:20:53 · answer #6 · answered by Missy 3 · 0 0

No, the foil method is for this kind of question (a+b)(c+d)

First, you multiply, then gather like terms and simplify.

8a-4b-3a+6b= 5a+2b! Hope this helps.

2006-10-12 14:20:23 · answer #7 · answered by Obi-wan Kenobi 4 · 0 0

You use "FOIL" when you are multiplying the sum of two things and the sum of two things. That is not this. Here, you distribute the 4 and the -3 (not 3 itself), and add.

2006-10-12 14:21:13 · answer #8 · answered by Anonymous · 0 0

No you distribut the 4 and the 3 and then you solve the like terms.

2006-10-12 14:19:38 · answer #9 · answered by . 6 · 0 0

no

2006-10-12 14:45:50 · answer #10 · answered by Ann 3 · 0 0

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