it's either the numbers 3,5,8, or all real numbers
2006-10-12 06:01:41 · 10 answers · asked by sammy 1 in Science & Mathematics ➔ Mathematics
all real numbers.
6-4x = 4(3-x)-6 = 12-4x-6 = 6-4x
6-4x = 6-4x
-4x = -4x
x = x
x can be anything for the equation to be true.
2006-10-12 06:05:07 · answer #1 · answered by MadScientist 4 · 1⤊ 0⤋
All real numbers. The right-hand side simplifies to
12-4x-6 or 6-4x. Since we have an identity here,
the solution set is the set of all real numbers.
2006-10-12 14:49:49 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
All numbers
6 - 4x = 12 - 4x - 6
6 - 4x = 6 - 4x
4x = 4x
Hence all numbers.
2006-10-12 13:05:13 · answer #3 · answered by Dr. J 2 · 1⤊ 0⤋
All real numbers.
6-4x=4(3-x)-6- Here both sides are equal.
(A real number may be either rational or irrational; either algebraic or transcendental; and either positive, negative, or zero.)
2006-10-12 13:08:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
6-4x = 4(3-x)-6
6-4x = 12-4x-6
6-4x = 12-6-4x
6-4x = 6-4x
6-6 = 4x-4x
0=0
--> does this make sense? LOLz...
2006-10-12 13:10:56 · answer #5 · answered by seXy 3 · 0⤊ 0⤋
All real numbers
2006-10-12 13:49:09 · answer #6 · answered by Claudia 3 · 0⤊ 0⤋
All real numbers
2006-10-12 13:05:09 · answer #7 · answered by ZOMBIEEE 2 · 0⤊ 0⤋
This equation reduces to
12 - 4x = 12 - 4x
which reduces to
0 = 0
Which is an identity...no solution.
Any answers you pose are incorrect.
Zero is Zero.
2006-10-12 13:08:06 · answer #8 · answered by zahbudar 6 · 0⤊ 0⤋
plug in each of the numbers in the possible answers for your variable. They all work, so the answer is real numbers
2006-10-12 13:10:19 · answer #9 · answered by alkenlem 2 · 0⤊ 0⤋
all real numbers.
2006-10-12 13:07:08 · answer #10 · answered by banghi 2 · 0⤊ 0⤋