I'm going this Saturday and debating on getting the fast pass... I need to know how crowded it will probably be.
2006-10-12 02:44:01 · 7 answers · asked by JustKc 2 in Games & Recreation ➔ Amusement Parks
Yes and yes....Definitely get the fast pass. My husband and I went last year before we knew I was preggo and the lines were ridiculous. The second we got the fast pass it made the day much more enjoyable. Mainly cause it's the fall, so it's more bearable to be walking around all day in the sun and also cause it's Halloween time! Have fun!
2006-10-12 02:52:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I am a ACE member - American Coaster Enthusiast - The best time to go to any amusement park is after the school year starts and it's even better if you go during the middle of the week like Tues. - Thurs. The kids are back in school and it's not as hot. If you have the money to waste, get the fast pass. Personally I think it's a waste of money this time of year. Hope this helps
2006-10-13 17:15:26 · answer #2 · answered by marstark7 1 · 0⤊ 0⤋
I havent been to that one, but i went to the one in maryland, and all amusements parks tend to busy during the school year, so i suggest going either really early during the day or 2 hours before closing time
2006-10-12 04:37:35 · answer #3 · answered by LJ 1 · 0⤊ 0⤋
how much does the fast pass cost and what exactly can you all do with it? my girlfriend and I are thinking about going before the end of the month. i havent been in years. im pretty excited about going back
2006-10-12 04:44:29 · answer #4 · answered by mistatnn 2 · 0⤊ 0⤋
No i live in geogia and go many times . most people go during the summer , be ready for people but not crowds
2006-10-14 04:11:06 · answer #5 · answered by cutiez 2 · 0⤊ 0⤋
GET THE SPEED PASS FOR SURE!
IT'S NOT ACTUALLY TOO MUCH CROWDED BUT YOU CAN HAVE A LOT OF FUN!!
HAVE FUN!
2006-10-15 07:35:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I want to say yes, but it will depend on the weather.
2006-10-12 06:48:44 · answer #7 · answered by Shane J 1 · 0⤊ 0⤋