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1. as x approaches pie/3, y = 10sinx

2. as x approached pie/6, y = 3800/sinx

2006-10-12 02:04:28 · 3 answers · asked by the man 2 in Science & Mathematics Mathematics

3 answers

1.dy/dx=10cosx
as x tends to pi/3=10(1/2)=5

2.dy/dx=3800(-cosecxcotx)
as x approaches pi/6=-3800(-2rt3)
=-7600rt3

2006-10-12 02:48:27 · answer #1 · answered by raj 7 · 0 0

1.
dy/dx = 10cos(π/3)

2.
dy/dx = -3800cos(π/6)/sin²(π/6)

These are fairly trivial problems. If you want me to take what will probably be a fairly trivial exam over this stuff for you, my rates are $125/hr (4 hr minimum) portal to portal plus travel expenses and $150.day per diem (if you're more than 100 miles from Tucson, AZ.). Lots of companies are happy to pay those rates because I know this (and a bunch of other) stuff.

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Doug

2006-10-12 09:46:03 · answer #2 · answered by doug_donaghue 7 · 0 0

"Rate of change" and "derivative" are the same thing.

To find the rate of change of these equations with respect to x, you need to calculated their derivatives with respect to x. Just use the derivative formulas.

Good luck!

2006-10-12 09:13:43 · answer #3 · answered by Carbon-based 5 · 0 0

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