There are 14 people at the supermarket?

Question

There are 14 people at the supermarket. 7 of them bought apples. 5 of them bought oranges. 4 of them bought neither. how many of them bought both types of fruits?
from p4 pupil & please explain your answer.

Answer 1

14 people were in the supermarket and 4 bought neither apples nor oranges. That leaves 10 who did. On the assumption that all of the 10 bought apples or oranges or both then we know that 7 bought apples. That leaves three who didn't so those 3 must have bought oranges only. Only 5 oranges were bought so that leaves 2 that were bought by the people buying apples.

So:
4 bought nothing
3 bought oranges
5 bought apples
2 bought apples and oranges

Answer 2

S=14 total people
A=7 people who bought Apple
O=5 people who bought Orange
(A u O)' = 4 people who bought neither

u = Union

(A u O) + (A u O)' = S
(A u O) = S - (A u O)'
(A u O) = 14 - 4
(A u O) = 10

Union people who bought either Apple or Orange or Both = 10

Intersection is the way to looking who bought both types.
(A n O) = A + O - (A u O )
(A n O) = 7 + 5 - 10
(A n O) = 12 - 10
(A n O) = 2

so the answer is 2 people bought both types of fruit

Answer 3

14 people in store -4 who bought neither=10 who bought at least 1.
7 bought apples+5 bought oranges-10who bought=
2 who bought both
7-2=5 who only bought apples
5-2=3 who bought only oranges so:

2 bought both
5 bought only apples
3 bought only oranges
4 bought neither

2+5+3+4=14 total.

Answer 4

14 people - 4 who bought neither = 10 who bought something
10 who bought something - 7 who bought apples = 3 who bought
only oranges
5 who bought oranges - 3 who bought only oranges = 2 who
bought both

answer 2 people bought both types of fruit

Answer 5

answer: 2. eliminate 4 of fourteen - they bought neither - leaving 10 we think bought SOMETHING. 7 of 10 bought apple. leaving 3 unknown. these 3 must have bought orange, leaving 2 of 7 apple buyers to also have bought oranges.

Answer 6

Actually 2 of them bought apples and oranges.

Answer 7

4 buy neither..

14-4=10

5 bought oranges

10-5=5

so 5 bought both apples and oranges..

Answer 8

4 buy nothing

then
number of people buying something=14-4=10
now
7 buy apples
5 buy oranges
then
by set theory
if a is the set of people buying apples and
b is the set of people buying oranges

n(aUb)=n(a)+n(B)-n(a intersection b)

10 = 7 + 5 -no. of people buying both apples and oranges
therefore no of peple buying both apples and oranges=12-10=2

thus answer is 2

Answer 9

there can't be those who bought both types of fruits as there are 16 in all.
well i'll explain it below:
total=14
apples=7
oranges=5
neither=4
7+5+4=16 i.e greater than the total number of peaple present in the supermarket!

Answer 10

14-4=7+5-intersection
two bought both
formula
n(aUB)=n(a)+n(B)+n(aintB)