(A) a skier is accelerating down a 30.0 degree angled hill at 1.80m/s^2. What is the vertical component of her acceleration?
(B) How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 335m?
2006-10-11 22:33:14 · 2 answers · asked by 3ajeeba_q8 2 in Science & Mathematics ➔ Mathematics
(A) The vertical component of the acceleration is given by 1.8m/sec^2 x sine 30 degrees = 1.8 x 0.5 = 0.9 m/sec^2
(B) Since she starts from rest and has a constant vertical acceleration the distance d = 335m = 1/2 x a x t^2 where a is the vertical acceleration = 0.9 m/sec^2 and t is the time in sec.
So t = sqrt(2xd / a) = sqrt(2 x335m / 0.9 m/sec^2) = 27.28 sec
2006-10-11 22:53:21 · answer #1 · answered by Jimbo 5 · 1⤊ 0⤋
huh?
2006-10-12 05:40:29 · answer #2 · answered by Amanda 2 · 0⤊ 0⤋