say how?
2006-10-11 21:48:27 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
for each one add 2 power its position-1
so 11110111 = 2^7 + 2^6 + 2^5 + 2^4 + 2^2+ 2^1 + 2^0 =247
since it has lots of 1's than zero's we can simply calculate as,
2^8 - 2^3 ( 2^(no of bits) - (sum of 2 power zero's postion -1 )
so its 256 - 9 = 247
2006-10-11 22:10:35 · answer #1 · answered by ksj_goblin 3 · 0⤊ 0⤋
1111 0111
notation: n^x = n to the x power
left side
(1)(2^7)+(1)(2^6)+(1)(2^5)+(1)(2^4) = 240
right side
(0)(2^3)+(1)(2^2)+(1)(2^1)+(1)(2^0) = 7
...add both together to get 247.
Binary is written in two's complement notation...read it, learn it, love it.
2006-10-12 05:03:44 · answer #2 · answered by entranced82 3 · 0⤊ 0⤋
367
2006-10-12 06:34:13 · answer #3 · answered by George P 1 · 0⤊ 0⤋
the value of 11110111 in decimal is 247..
2006-10-12 04:53:52 · answer #4 · answered by buntykawale 1 · 0⤊ 0⤋
=1*2^7+1*2^6+1*2^5+1*2^4+0*2^3+1*2^2+1*2^1+1*2^0
=1*2^7+1*2^6+1*2^5+1*2^4+0*2^3+1*2^2+1*2^1+1*2^0
=128+64+32+16+0+4+2+1
=247
2006-10-12 05:23:14 · answer #5 · answered by safrodin 3 · 0⤊ 0⤋