If a/b>c then what is a/b^2 ? Tell me the answer with respect to c.?

Answer 1

If a and b are all positive numbers,

a/b > c
a/b*(1/b) > c*(1/b)
a/b^2 > c/b

Counterchecking,

Let a = 9, b = 3, c= 2,
9/3 > 2
9/3*(1/3) > 2*(1/3)
1 > 2/3, or 9/3^2 > 2/3

This question gets alot more complicated if put negative numbers into the variables. I'm trying that out now.

Answer 2

a/b^2 > c/b

Answer 3

Undetermined. supose a=6, b=2 & c=1 then
6/2>1 is true
(6/2)^2=9 is greater than c, c^2 etc.
Now let a=1, b=2 & c=1/3
1/2>1/3 is true but (1/2)^2 =1/4 is less than 1/3 but greater than c^2
next let a=-4, b=1 & c=-6
-4/1>-6 but while 16>-6, 16<36

Answer 4

a/b>c mean,
a/b^n>,<, or = to c, as n is in denominator.

suppose , a=6,b=2,c=2
then,
a/b=6/2=3>c
but for a fix value, a/b^2 term will have lesses and lesser value.
it also depend the value of a,b or c is having positive or negative value.

Answer 5

if a/b > 0
(a/b)^2 > c^2
otherwise
(a/b)^2 < c^2

I think...try it out with some example numbers.

Answer 6

1.9999999999 and below...
including negatve integers..