Hai friends these maths problems shows 0=1=2=3=4=5= 6=7=8.... ......... ..infinity
if u think different u can get more wonders with numbers
Therm 1)
4==5
(4-(9/2))^2= =(5---(9/ 2))^2
(-1/2)^2==(1/ 2)^2
apply root both sides
then cancel squre both sides
1/4==1/4
so 4==5
-1 both sides
so 3==4
-1 both sides
so 2==3
as per a=b,b=c --------->a=c so
1=2=3=4=5=6= 7=8
Therm 2)
(-12)==(-12)
9-21==16-28
add 49/4 both sides
9-21+(49/4)= =16-28+(49/ 4)
3^2--2*3*(7/ 2)+(7/2)^ 2==4^2--2* 4*(7/2)+( 7/2)^2
it is a^2+b^2-2ab= =(a-b)^2
so apply this formula
(3-(7/2))^2= =(4-(7/2) )^2
apply root both side
and cancel squres
(3-(7/2))==( 4-(7/2))
so 3==4
Therm 3)
0==0
a^2-a^2==a^2- a^2
a*(a-a)==(a+ a)(a-a)
cancel (a-a) both sides
so
a=(a+a)
if a=1
1=2
Therem 4)
-20==-20
16-36==25-45
add 81/4 both sides
16-36+(81/4) ==25-45+( 81/4)
apply a^2+b^2-2ab= =(a-b)^2
(4-(9/2))^2= =(5-(81/4) )^2
finally u get
4==5
2006-10-11
20:40:02
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7 answers
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asked by
rameshgavva
2
in
Science & Mathematics
➔ Mathematics