No, the two Hepburns were not related.
Hepburn was not Audrey's real name. She was born ANDREY KATHLEEN RUSTON in Brussels, Belgium on May 4th 1929.
KATHERINE HOUGHTON HEPBURN was born on May 12th 1907 in Hartford, Connecticut.
Katherine was related to actress Katharine Houghton, her niece, and the two worked together in the film "Guess Who's Coming to Dinner" (1967).
2006-10-11 18:23:06
·
answer #1
·
answered by Anonymous
·
3⤊
2⤋
That is not a stupid question at all.
It is sometimes claimed that Audrey Hepburn and Katharine Hepburn were related. The truth is they were only very distantly related, and certainly had never met before the former's rise to prominence. The closest relationship that has been identified for them is 19th cousins once removed. It has also been claimed that Audrey chose the last name Hepburn in honor of Katharine when she became an actress; however, the record shows that it was part of her family name for some time before she entered show business.
2006-10-11 18:23:41
·
answer #2
·
answered by Perplexed Music Lover 5
·
2⤊
0⤋
No. Katherine Hepburn was born in New England and Audrey was British.
2006-10-11 18:25:44
·
answer #3
·
answered by Joanne B 3
·
0⤊
1⤋
Everyone else knew the answer, I didn't. But just wanted to say, its not a stupid question. Trust me, I've been reading a lot more stupid questions on this site than what you asked.
2006-10-11 18:30:20
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
Yes.....but very distant.
The links below all support this but there is some links that dispute it.
The last link is the google link for them all!
2006-10-11 18:34:36
·
answer #5
·
answered by cooter_1us 2
·
1⤊
0⤋
No, they are not related in any way.
2006-10-11 19:40:49
·
answer #6
·
answered by Anonymous
·
0⤊
1⤋
no, way to go Kitch..lol
2006-10-11 18:28:14
·
answer #7
·
answered by oneblondepilgrim 6
·
0⤊
1⤋
mom and daughter
2006-10-11 18:30:50
·
answer #8
·
answered by 6ft5inallman 2
·
0⤊
5⤋
yep, stupid question indeed, they are sisters
2006-10-11 18:24:48
·
answer #9
·
answered by Anonymous
·
0⤊
12⤋