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Sixty percent of those present at the performance were neophytes. If 200 present were not neophytes, how many people attended the performance?

2006-10-11 17:33:18 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

Since 60% were neophytes, the other 40% are not.
So, 200 people is 40% of the total people attending the performance.

200/4 = 50. Every 10% is 50 people. So, 100% would be 50*10 or 500 people =)

You can check this by multiplying the 500 * .40 = 200 people. Yay.

=)

2006-10-11 17:37:17 · answer #1 · answered by flossie116 4 · 0 0

If there are 60% neophytes, then there must be 40% that are not neophytes. Given that there are 200 that aren't neophytes, we can set up an equation to find the total amount of people who attended the performance:

200 = Total * 0.4
Total = 200/0.4 = 500

Therefore, 500 people attended the performance. Of course, you can verify this: 500 total * 0.6 = 300 neophytes.

2006-10-12 00:39:00 · answer #2 · answered by Anonymous · 0 0

60% = Neophytes.
→ 40% ╪ Neophytes.
40% = 200 (÷ 40)
1% = 5 ( x 100)
100% = 500

2006-10-12 00:53:42 · answer #3 · answered by Brenmore 5 · 1 0

1 - 60/100 = 40/100
40x/100 = 200
x = 10*200/4

2006-10-12 00:40:25 · answer #4 · answered by Helmut 7 · 0 0

500 people cause every 20% is 100 people so 60% is 300 people, and there for 200 is 40%.

2006-10-12 00:41:11 · answer #5 · answered by thamastakush 2 · 0 0

40% = 200

100%
= 200/40 x 100
=500

2006-10-12 03:48:11 · answer #6 · answered by yukki_b 2 · 1 0

334

2006-10-12 00:39:17 · answer #7 · answered by CHAD M 2 · 0 1

.4T=not neophytes (60% are, so 40% aren't)
.4T=200
T=200/.4
T=500

500 people

2006-10-12 00:38:19 · answer #8 · answered by Anonymous · 1 0

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