Jonice has decided to sail around the world. She starts off moving East with a speed of 40 m/s. The ocean currents are pushing her north with a speed of 15 m/s. What is her resultant speed?
2006-10-11 16:59:29 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
I could be wrong but I would of thought that if she is travelling at 40 m/s then that is the speed she is travelling at..
The currents are pushing her at 15 m/s so she is powering the boat at 25 m/s and the current is making it up to 40
2006-10-11 17:02:55 · answer #1 · answered by Paul 5 · 0⤊ 0⤋
Resultant speed is given by
=>sqrt.(15^2 + 40^2)
=> 42.72 m/s in North-East direction.
(here, as u want to know the velocity, mention of direction is necessary).
2006-10-12 00:10:13 · answer #2 · answered by Innocence Redefined 5 · 0⤊ 0⤋
WKT R = sqrt(P*P+Q*Q+2PQcostheta)
R = sqrt(15*15+40*40+2*15*40cos 90)
R = sqrt(225 + 1600 + 0)
R = sqrt(1825)
R = 42.720 m/s
Angle is = tan^-1(Qsin theta/P + Qcos theta)
tan^-1(15 sin(90)/40 + 15 cos 90)
tan^-1(15/40)
tan^-1(0.375)
20.556
The resultant speed is 42.270 m/s and it is at an angle 20.556 with respect to the force of Jonice's boat
2006-10-12 00:23:57 · answer #3 · answered by Enrique 2 · 0⤊ 0⤋
(40^2 + 15^2)^(1/2) = 42.72 m/s
2006-10-12 00:09:48 · answer #4 · answered by Stewart H 4 · 0⤊ 0⤋
(40ms)2 + (15ms)2 = R2
10 000 km2/hr2 + 625 km2/hr2 = R2
1600 + 225 = R2
SQRT(1825) = R
42.72 M/S = RESULTANT SPEED
As illustrated here
http://www.glenbrook.k12.il.us/gbssci/phys/Class/vectors/u3l1f.html
2006-10-12 00:07:25 · answer #5 · answered by lushads 3 · 0⤊ 0⤋
42.72 m/s
2006-10-12 00:06:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋
45,000 m/s
2006-10-12 00:00:29 · answer #7 · answered by Jason M 2 · 0⤊ 0⤋