solve (f - g) (x) and (f - g) (1)?

Question

Given f(x) = 5+ 2/x and g(x) = x-1

Answer 1

(f - g) (x) = f(x) - g(x)
f(x) = 5+ 2/x and g(x) = x-1
so:
(f - g) (x) = 5+ 2/x - (x-1)
= 5 + 2/x - x + 1
= 6 + 2/x - x (solution!) or: (-x^2 + 6x + 2) / (x)

(f - g) (1) = 6 + 2/1 - 1 = 7 (solution!)

Answer 2

I'm a bit rusty, so you might get a better answer.
Put everything over a common demoninator of x.
that gives you 4x^2/x + 2/x + x/x , x cant equal zero
for the second part I substituted 1 in place of x and got 7