An object slides down an inclined plane of angle 20° and of incline length 4 m. If the initial speed of the object is 6 m/s directed down the incline, what is the speed at the bottom? Neglect friction.
2006-10-11 16:30:49 · 3 answers · asked by nt 2 in Science & Mathematics ➔ Physics
The acceleration down the 20 deg frictionless incline would be
a = g x sin (20 deg) , g = 9.8 m/s^2
The speed at the bottom is
V = v1 + a x time , v1 = 6 m/s
The distance traveled is 4 m
d = v1x time + (1/2)x a x (time^2) = 4 m
Solve the distance formula for time
Plug that time into the velocity formula and you're done.
2006-10-11 16:41:25 · answer #1 · answered by Roadkill 6 · 0⤊ 0⤋
Wow....that just gave me a migraine.
But good luck trying to figure out the answer.
2006-10-11 23:34:24 · answer #2 · answered by julygirl75038 3 · 0⤊ 0⤋
oh huh
2006-10-11 23:32:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋