Multiply these fractions 2x^2 - x - 3 over 3x^+7x+4 times 3x^2-11x-20?

Question

Multiply these fractions 2x^2 - x - 3 over 3x^2+7x+4 times 3x^2-11x-20 over 4x^2 - 9

Can someone show me how to do this?

Answer 1

You have to factor your polynomials into two binomials. You'll get
(2x-3)(X+1)over (3x+4)(x+1) and (3x+4)(x-5)over (2x-3)(2x+3)

You can cancel out any numerator binomial that matches a denominator binomial. The ones left will be (x-5)/(2x+3)

Answer 2

((2x^2 - x - 3)/(3x^2 + 7x + 4)) * ((3x^2 - 11x - 20)/(4x^2 - 9))

((2x^2 - x - 3)(3x^2 - 11x - 20))/((3x^2 + 7x + 4)(4x^2 - 9))

((x + 1)(2x - 3)(x - 5)(3x + 4))/((x + 1)(3x + 4)(2x - 3)(2x + 3))

Take out the (x + 1)(2x - 3)(3x + 4)

ANS : (x - 5)/(2x + 3)

Answer 3

factor the equations

(2x-3)(x+1)/(3x+4)(x+1)
times
(3x+4)(x-5)/(2x+3)(2x-3)


cancel all the similar factors
-- 2x-3
-- 3x+4
-- x+1

what's left is x-5 over 2x+3

so, that's the answer

Answer 4

Same as any fraction, but polynomial hell. for instances

2x^2 * 3x^2=6x^4 have fun!!