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If anyone can help me out with this I would really appreciate it :) I am stuck on this problem.

A 2.00 kg block situated on a rough incline is connected to a spring of negligible mass having a spring constant of 100 N/m (see the figure that I linked below). The block is released from rest when the spring is unstretched, and the pulley is frictionless. The block moves 19.0 cm down the incline before coming to rest. Find the coefficient of kinetic friction between the block and incline.

http://www.webassign.net/sf/p5_76.gif

2006-10-11 15:56:33 · 1 answers · asked by Michelle 1 in Education & Reference Homework Help

1 answers

OK. Let's set up an equation:

The block slides down the incline with a force that equals it's weight times the sine of the angle of incline. (opposite = down, hyp = the incline).

At 19.0 cm, the total force must be 0, because the block comes to rest. Therefore:
Fg = Ff + Fs
where Fg is from gravity, Ff is from friction, and Fs is from the spring.

Fs = kx = 100Nm * .19 m = 19N.
Fg = mg * sine(angle) = 2 * 9.8 * sine(angle) = 19.6 * sine(angle)
Ff = μFg

Thus:
19.6 sin(angle) = 19.6 sin(angle) * μ+ 19
19.6 sin(angle) - 19 = 19.6 sin(angle) *μ
μ = 1 - (19/19.6 sin(angle))
μ = 1 - 0.9694 * sin(angle)

All you need left is the angle of incline. (your link didn't work).

2006-10-12 01:24:43 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

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