(12x^3 + 20x^2 + 6x + 17) divided by (3x + 5)
the answer in form of Q(x) + R(x)/3x+5, where
Q(x) is the quotient and R(x) is the remainder
of the division..
help, its another one thats killing me
2006-10-11 15:27:45 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Used synthetic division.
(12x^3 + 6x + [7/(3x+5)])
Remainder is 7/(3x+5).
2006-10-11 15:32:14 · answer #1 · answered by Anonymous · 0⤊ 0⤋
12x^3 divided by 3x = 4x^2
4x^2 * 5 = 20x^2
12x^3 + 20x^2 -- from the given problem
minus
12x^3 + 20x^2 -- from the answers written above
equals
0
since the answer is 0, we jump to the third term
note: in case the answer is non zero, divide it by 3x, and so on.. as given above
6x -- third term of the given problem
divided by 3x = 2
2 * 3x = 6x
2 * 5 = 10
6x + 17 -- third and fourth term
minus
6x + 10
equals
7
so, the remainder is 7/3x+5
answer:
4x^2 + 2 + 7/3x+5
2006-10-11 22:41:30 · answer #2 · answered by kezongputi 2 · 0⤊ 0⤋
Do you know how to do long (synthetic) divisions?
There is no use if I give you the answer. Check this website:
http://www.purplemath.com/modules/synthdiv.htm
2006-10-11 22:40:37 · answer #3 · answered by smarties 6 · 0⤊ 0⤋
quotient is: 4x^2 + 2
Remainder: 7
2006-10-11 22:34:30 · answer #4 · answered by quark_sa 2 · 0⤊ 0⤋