ln A = ln h - ln(1 - h)
Solve for h
2006-10-11 14:42:39 · 4 answers · asked by HJS 1 in Science & Mathematics ➔ Mathematics
ln (A) = ln h - ln(1-h)
ln (A) = ln (h/(1-h))
A = h/(1-h)
h = A(1-h)
h = A - Ah
h + Ah = A
h (1 + A) = A
h = A/(1+A)
2006-10-11 15:22:09 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋
ln A = ln h - ln (1-h) = ln(h / (1-h))
Thus A = h / (1-h)
A - Ah = h
A = h + Ah
A= h (1+A)
h = A / (1+A)
2006-10-11 14:55:49 · answer #2 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
ln h - ln(1-h) = ln h/(1-h)
ln A = ln h/(1-h)
A = h/(1-h) and it should be piece of cake from here ah?
2006-10-11 15:00:01 · answer #3 · answered by Dr. J. 6 · 0⤊ 0⤋
h = a/(1+a)
ln (A) = ln h - (1-h)
ln (A) = ln (h/(1-h))
A = h/(1-h)
h = A(1-h)
h = A - Ah
h + Ah = A
h (1 + A) = A
h = A/(1+A)
2006-10-11 14:51:42 · answer #4 · answered by Meemah 3 · 0⤊ 0⤋