solve for "x" (x/x+4) = (4/x-4) - (28/x^2-16)?

Question

This is one fraction minus another fraction to equal yet another fraction

Answer 1

im assuming that you mean:
x/(x+4)=4/(x-4)-28/(x^2-16)

multiply both sides by (x+4)(x-4) since it is the least common denominator (x^2-16)=(x+4)(x-4) since it's a difference of squares

x(x-4)=4(x+4)-28
x^2-4x=4x+16-28
x^2-8x+12=0
(x-6)(x-2)=0
x=either 6 or 2

Answer 2

Get rid of the fractions by multiplying by the lowest common denominator, which is (x+4)(x-4), or x^2-16

x(x-4)=4(x+4)-28
remove ()
x^2-4x=4x +16-28
subtract 4x, add 12 to both sides
x^2 -8x +12=0
factor
(x-6)(x- 2)=0
set each factor =0 and solve
x-6=0, so x=6
x-2=0, so x=2

Answer 3

(x/(x + 4)) = (4/(x - 4)) - (28/(x^2 - 16))

Multiply everything by (x + 4)(x - 4)

x(x - 4) = 4(x + 4) - 28
x^2 - 4x = 4x + 16 - 28
x^2 - 4x = 4x + 12
x^2 - 8x + 12 = 0
(x - 6)(x - 2) = 0

x = 6 or 2

Answer 4

x/(x+4)=4/(x-4)-28/((x-4)(x+4))
where (x^2-16)=(x-4)(x+4)
so: muliply all tew equation by ((x-4)(x+4))
so: x(x-4)=4(x+4)-28
x^2-4x=4x+16-28
x^2-8x+12=0
(x-6)(x-2)=0
so the answer
x=6
x=2
besr chance

Answer 5

x/4 sixteen/60 whenever you have a fraction resembling a fraction, you're in a position to do away with stated fractions making use of bypass multiplication. this form you have in ordinary terms one line to artwork with. it somewhat is finished with appropriate here formula: a/b = c/d will become advert = bc. making use of this: x/4 = sixteen/60 will become: 60x = sixty 4 Now, we in ordinary terms divide by way of capacity of x: x = sixty 4/60 And simplify: x = sixteen/15

Answer 6

i think you multiply x times x then x time 4 and add it up. well is hard to explain i have to write it not type it. sorry.

Answer 7

x = Phoenix?

Answer 8

x = 9.22087