39c-33c+78=0
36c+78=0
36c=-78
c=-13
2006-10-11 13:23:10
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answer #1
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answered by kitmitzi 2
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Just like any other algebra problem, you must isolate the variable. It doesn't get much more basic than this. ONE variable and a little basic math (add, subtract, mult., div). Remember, whatever you do to one side of the equation, you must to do the other. What can you do to get the term with the coefficient and variable on one side and the 78 on the other? Then, what can you do to both sides to get the C all by itself? Think in terms of mathematical "opposites". For example, right now 39c is added to 78... what can you do to both sides of the equation to get the 39c over to the other side?...what is the "opposite" of adding?
2006-10-11 13:24:54
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answer #2
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answered by Anonymous
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you take the 33c and minus it from 39c and then move the 78 to the other side of the equal sign and it will be -13.
39c - 33c = -78
6c = -78
divide each side by 6 and it will be C=-13
2006-10-11 13:25:52
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answer #3
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answered by S B 3
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39c-78=33c
39c=33c-78
6c=-78
-78/6=-13
c= -13
I had a hard time with Algebra too, but I had like the best teacher in the world he made it seem like common sense. My Email is fiftyfleetliner@yahoo.com if you ever need more help.
2006-10-11 13:27:20
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answer #4
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answered by Anonymous
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39c+78=33c
Subtract 33c from both sides.
6c+78=0
Subtract 78 from both sides.
6c=0-78
6c=-78
Divide both sides by 6.
1c=-78/6
c=-13
2006-10-11 13:28:46
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answer #5
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answered by Robert B 5
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group your c variable together (subtract from each side) divide the 78 by the number left in front of c. That will give you C=
2006-10-11 13:23:03
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answer #6
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answered by Anonymous
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C = -13
2006-10-11 13:22:21
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answer #7
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answered by Vegetaf 2
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39c+78=33c
78=33c-39c
78=-6c
c=78/-6
c--13
2006-10-11 13:30:07
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answer #8
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answered by beach_puppy_9 1
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