The area of a square is 36. What is the length of the diagonal of the square ?
2006-10-11 12:59:56 · 3 answers · asked by Monique 1 in Science & Mathematics ➔ Mathematics
6Sqrt(2)
2006-10-11 13:02:55 · answer #1 · answered by Greg G 5 · 0⤊ 0⤋
Realize that to get the area you have to take length time width.
So, since this is a square, the length and the width is 6.
Now, you want the diagonal.
a^2+b^2=c^2
6^2+6^2=c^2
36+ 36 = c^2
72=c^2
c = square root of 72
72 is not a perfect square, but this can be be reduced
72 = 8 *9. 8 is not a perfect square, but can be reduced again, 9 is a pefect square
So square root of 72 = square root of 9 *4*2
Square root of 9 is 3 and square root of 4 is 2
So Square root of 72 = 6 square roots of 2 is the diagonal of the square.
2006-10-11 20:07:19 · answer #2 · answered by danjlil_43515 4 · 0⤊ 0⤋
square=36
Length[L]=Width[W]=Square root of 36
L=W=6
Diagonal of square
D^2=L^2+W^2
D^2=6^2+6^2
D^2=36+36
D^2=72
D=SQRT(72) square root of 72
D=8.4852813742385695
D=8.485
2006-10-11 20:06:26 · answer #3 · answered by safrodin 3 · 0⤊ 0⤋