Lunches for three brothers Adam, Ben, and Carl are made and the lunch bags are marked with their names. It's dark when they leave for school. They each pick up a lunch bag as they go out the door.
QUESTION:
What is the probability that no one gets their own lunch?
2006-10-11 12:53:06 · 6 answers · asked by aguila09@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics
Hi. 1 in 9.
2006-10-11 12:56:49 · answer #1 · answered by Cirric 7 · 0⤊ 1⤋
There are six different scenarios for who gets what lunch. In those scenarios there are two in which they ALL get the wrong lunch. So the probability is 2/6 = 1/3.
A B C
--------
A B C They all get the right lunch
A C B Only Adam is right
C B A Only Ben is right
B A C Only Carl is right
C A B No one gets the right lunch
B C A No one gets the right lunch
2006-10-11 20:10:52 · answer #2 · answered by just♪wondering 7 · 0⤊ 0⤋
123 Yes
213 Yes
312 No
132 Yes
231 No
321 Yes
2/6=1/3=33%
2006-10-11 20:18:34 · answer #3 · answered by Don't look too close! 4 · 0⤊ 0⤋
33.3%
There are six possible out comes, the first two outcomes have Adam getting his own lunch, of the other four which include Adam getting Bens or Carls lunch(twice each), Ben in each case has a 50% chance of getting Adams lunch. 50% of 4 is 2, 2chances from 6 equals 33.3%
2006-10-11 20:11:22 · answer #4 · answered by Mark Antony 3 · 0⤊ 0⤋
51
2006-10-11 19:55:46 · answer #5 · answered by doryjay 2 · 0⤊ 1⤋
2 out of 6 so it is 1/3
A gets B's, B gets C's, C gets A's
or
A gets C's, B gets A's, C gets B's
if you want to use formula, it is 2/3 x 1/2 = 1/3
2006-10-11 19:58:24 · answer #6 · answered by buaya123 3 · 1⤊ 0⤋