2006-10-11 12:17:22 · 4 answers · asked by robert h 1 in Science & Mathematics ➔ Physics
2000 ft = 50.8 m
Now use Newton's law of gravitation:
F = G(Me*m / (Re+r)^2) = ma
a = G(Me/(Re+r)^2) = 9.81 m/s^2
(not a significant change)
Constants:
Re = radius of Earth = 6.37x10^6 m
Me = mass of Earth = 5.93x10^24 kg
G = 6.67x10^-11 Nm^2/kg^2
2006-10-11 12:31:44 · answer #1 · answered by Anonymous · 0⤊ 0⤋
acceleration due to gravity at sea level is symbolized by 'g'. this 'g' is equal 9.81 m/s^2.
'g' changes soooooooo very little when mesuared at 2000 feet instead of at sea level, that the change is totally negligible. so at 2000 feet, the acceleration due to gravity still is 9.81. just like at sea level.
2006-10-11 19:36:25 · answer #2 · answered by dudyu 1 · 0⤊ 0⤋
I though it was always 9.81m/s2
2006-10-11 19:30:15 · answer #3 · answered by mfacio 3 · 0⤊ 0⤋
9m/s^2
2006-10-11 19:24:32 · answer #4 · answered by roberticvs 4 · 0⤊ 0⤋