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A 1563.4 kg car is traveling at 25m/s when the driver takes his foot off the gas pedal. It takes 4.9 s for the car to slow down to 20m/s. How large is the net force slowing the car ? Answer in units of N.

2006-10-11 11:36:24 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

F=ma

F1=0 because there is no accelleration initially

F2=(1563.4kg)((25m/s)/(4.9s))

Subtract F2 from F1 and there is your answer.

(kg)(m/s^2) is a N

2006-10-11 11:41:56 · answer #1 · answered by chica1012 2 · 1 0

i wont give the answer to your question. do your homework. btw thanks for the 2 points i get for answering this question hahaha.

2006-10-11 19:20:43 · answer #2 · answered by Anonymous · 0 0

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