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Solve this system by the most convenient algebraic method.

x = 2 y + 6
3 x = 4 y + 8

2006-10-11 11:05:04 · 5 answers · asked by Korey's Mamacita 1 in Science & Mathematics Mathematics

5 answers

Hi again dear;
the solution is as same as your ex -question '
x = 2 y + 6
3 x = 4 y + 8 → 3x - 4y = 8
Step 1
fill the value of x in the second function ;

3*( 2y + 6 ) - 4y = 8
6y + 18 - 4y = 8
2y = 8 - 18
2y = -10
y = -10/2
y = -5

Step 2
fill the value of ' y ' in to one of the functions ;
x = 2 (-5) + 6
x = -10 + 6
x = -4

The Result is
x = - 4
y = -5

Good Luck Dear.

2006-10-11 11:56:21 · answer #1 · answered by sweetie 5 · 7 1

Using the first equation we can multiply x by 2. Therefore the other side of the equation has to be multiplied by 2.

2x = 4y + 12

Then, ce can put the equation in this order:

4y= 2x - 12

We now use the 2 equation that you got.

3x = 4y + 8 , but because of the first equation we know that 4y = 2x - 12 so we replace 4y in the 2nd equation.

3x = (2x - 12) + 8 and then just solve for x.

x= -4

Because of the 1st equation we know that 4y = 2x - 12 so we replace again with the value of x we've just got.

4y = 2 (-4) - 12.
4y = -8 - 12
4y = -20

y= -5

2006-10-11 18:06:53 · answer #2 · answered by Sergio__ 7 · 0 0

I would start by multiplying the top equation by 3 to get:
3x=6y+18 next just set these two equations equal to each other:
6y+18=4y+8 and solve
2y=-10
y=-5 substitute this back into the orininal to get x:
x=2*-5+6=-4
Therefore, the answer is (-4,-5)

2006-10-11 18:11:54 · answer #3 · answered by bruinfan 7 · 0 0

putting tje value of x from 1st equation in 2nd equation
then
we get
3(2y+6)=4y+8
6y+18=4y+8
2y=-10
y=-5
putting value of y we get
x=2(-5)+6
x=-4
therefore answer is
x=-4; y=-5

2006-10-11 18:09:53 · answer #4 · answered by Anonymous · 0 0

x= -4
y= -5

2006-10-11 18:16:55 · answer #5 · answered by Nimooka 1 · 0 0

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