What is the equation of a line that passes through (2, 2) and (2, - 3)?
2006-10-11 10:24:28 · 4 answers · asked by britiani j 1 in Science & Mathematics ➔ Mathematics
First thing to do is find the slope using the equation m = (y2 - y1)/(x2 - x1). Then use that slope and either point in the point-slope equation: y - y1 = m(x - x1). Plug in your values for m, x1, and y1, then simplify.
2006-10-11 10:29:24 · answer #1 · answered by tlf 3 · 0⤊ 0⤋
Work:
Normally, I would use the equation for slope (change in y/change in x), but I noticed that the x coordinate is the same for both points. This means that there is no slope, or a vertical line, and therefore, no y-intercept. Regardless of the y coordinate, the x is always 2. Therefore, there is no y variable in the equation, which is:
x=2
2006-10-11 17:29:34 · answer #2 · answered by Squeaky 2 · 0⤊ 0⤋
These points have the same x-value, 2, so this line is vertical. Therefore, it has the equation x=2.
2006-10-11 17:29:11 · answer #3 · answered by James L 5 · 1⤊ 0⤋
That would be a vertical line whose x-intercept is 2.
The equation is: x = 2
2006-10-11 17:30:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋