1101 in decimal notaion would be ? illustrate?

Answer 1

I figure you're referring to a binary to decimal conversion?

Binary works on powers of two: 1 2 4 8 16 32 64 128 256 512 1024, etc. However we read from right to left: ...1024 512 256 128 64 32 16 8 4 2 1. And we map the binary representation to this model by placing the binary values (either a zero or one) beneath the corresponding power of two, like so (again, starting from the right):

...128 64 32 16 8 4 2 1
............................1 1 0 1

Now to convert it to decimal, all we need do is follow this simple logic: 1 lot of 1, 0 lots of 2, 1 lot of 4 and 1 lot of 8. (Ignore the periods above, I needed them for formatting.) Add that all together and we have 13.

Now, as an exercise, covert the number 321 to binary.

(And if you feel like using a calculator then the one that comes packaged with Windows handles binary, decimal, hexadecimal and octal conversion. Just click on the View menu, select Scientific, and directly below the read-out, to the left, is where you can select the notation.)

Answer 2

Let's start with numbers we are most used to working with. They are base 10, the correct term for decimal notation. Take the number 6,342
You have 6 lots of 1000
you have 3 lots of 100
you have 4 lots of 10
and 2 lots of 1's (or units)

And all numbers are made up in the same way.

Now you have to sort of think of the way a number is written as if it is 'back to front':
Units ; 10s ; 100s ; 1000s ; and so on.

Now think of these numbers as multiples of 10:
1 ; 10 ; (10*10) ; (10*10*10) ; (10*10*10*10)
- or 1, 10, 10²,10³ and so on!
Now, instead of 10, use the word base:

unit base (base*base) (base*base*base) (base*base*base*base)
This is how all numbers work, whether you are working in binary, base 10 - or even base 23!

Now, because you are working in base 2, put 2 where we had the word 'base':
1;2;(2*2);(2*2*2);(2*2*2*2)

This gives you:
1;2;4;8;16
then turn it back the correct way round:
16;8;4;2;1

Using the number you gave us, 1101, write it under the bits we need:

16 8 4 2 1
--- 1 1 0 1

Thus we have:
one lot of units:
no lots of twos
one lots of fours
one lot of eights

next work these out:
1*1=1
0*2=0
1*4=4
1*8=8
then add the numbers together:
1+0+4+8=13

So 1101 in binary is 13 in base 10.
But can you reverse this?

13 divided by 2 = 6 remainder 1
6 divided by 2 = 3 remainder 0
3 divided by 2 = 1 remainder 1
And the bit left over:1

put down the remainders in order, working from the bottom to the top:
1101

hope you understand this now!

Answer 3

13

1 1 0 1
8+4+X+1 =13

Answer 4

you'll have to be more specific in your question. if 1101 is a whole number...then the decimal would be placed after the ones digit...so you would have 1101.000 (and zeros after the decimal).
the first repsondent was mistakened, you can have as many digits before or after the decimal, depending on the number.
the second who referenced binary system (base 2) was correct, if your 1101 is written in base 2. you have one set of ones, no sets of twos, one set of fours and one set of eights. and converting it to our regular base 10, you get 8+4+0+1 which is 13.

Answer 5

no only a max of two numbers can go after the decimal point, as many can go before it, so the answer is 1101.00
if u answer 1.101 you are reducing the actual value of the question/sum

Answer 6

I'm guessing it is binary, so the answer is: 13
As in 8+4+0+1

Mike Honeycutt

Answer 7

1.101 because there can only be one number in front of the decimal