What do you do when graphing y=3?

Question

I have to solve this by graphing:
3x-2y=6, and
y=3
I know what to do for the first part, but I'm not sure how to graph y=3. I am using the set up where it looks similar to this:
x | y < where you fill in the blanks, sorta.
|
|
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Where is the x? How do I graph it? I will reply if you need more infromation. thank you!

Answer 1

Draw a verticle line at x = 3

Answer 2

Well y is the value for a certain number. The x axis could be represented by any number. Like in the example y=3. You are missing x. So when graphing the plot x could be any number of your choice. So the answer for y=3 the order pair could be (1,3), (2,3), etc... All you have to do is put any number for x and the y has to be 3.

Answer 3

the problem is quite easy if you under stand this

the examiner gives you all the information you need in the equation.....in this equation the examiner tells you that the value of y is 3 now it means that whatever the value of x may be the value of y will always be 3 therefore whn you plot this graph the value of x can be anything but value of y will always remain 3 therefore your plot must look like line prallel to x axis pssing through 3on y axis
draw the other equtions graph by plugging in the values

the point where both the lines cut is the solution to this problemwhich in this case willbe (0,3)

Answer 4

Solve the equation y = 3/2x - 3

and put in poinst for x, say x= 0 then y = -3, x= 2 and y = 0,

plot the points one at a time then draw a line.

Answer 5

x in this case varies from -infinity to +infinity and y remains a constant = 3. Thus the equation y = 3 is a straight line parallel to the x axis and passing through x = 0, y = 3, i.e. +3 units away from the x axis and parallel to the x axis

Answer 6

X would be zero in this case. So the literal point is (0,3). You go zero to the right and 3 straight up. That basically means go 3 up from the origin. Then make a horizontal line.

Answer 7

3x-2y=6

y=3

3x-2*3=6

3x=6

subtract the 3 from the 6

answer
x=3

Answer 8

y=3 is a horizontal line passing through (0,3)

Answer 9

Find y = 3 on the graph, on the y-axis. Basically, find the point (0,3). Now, draw a horizontal line from that point to BOTH ends of the graph. That is how you graph y=3. Let me make this more visual:


_|_4|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|
_|_3|_|_______________________________________________
_|_2|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|
_|_1|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|
_|_0|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|_|

Answer 10

All you have to do is draw a horizontal line three units up from the x-axis.
y-axis
I
I
I
---------------------y=3
I
I
I
---------------------x-axis