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y^2-y+5/y+4

2006-10-11 09:40:27 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Assuming what you wrote is what you meant The equation is invalid when y=0, since the equation will go to +inf.

However if you meant (y^2-y+5)/(y+4) then:
The equation would be invalid at y = -4 for the same reason

2006-10-11 09:43:58 · answer #1 · answered by Mariko 4 · 0 0

y^2-y+5/y+4 is undefined when y=0

(y^2-y+5)/(y+4) is undefined when
y+4=0, i.e. y = -4

2006-10-11 18:32:18 · answer #2 · answered by locuaz 7 · 0 0

I assume you mean (y^2-y+5) / (y+4), and you want to know where it's undefined?

It's undefined at y=-4, because that is where a division by zero would occur.

2006-10-11 16:42:50 · answer #3 · answered by James L 5 · 0 1

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