little help please......... divide?

Question

x+2 divide 3x*2+10x+15=
thanks for any help

Answer 1

I assume you want to divide 3x^2 + 10x + 15 by x+2.

Divide the leading terms: 3x^2/x = 3x. That is the first term in your quotient.

Next, compute
3x^2+10x+15 - 3x(x+2) =
3x^2+10x+15 - 3x^2 - 6x =
4x+15

Now divide 4x+15 by x+2. Divide leading terms again: 4x/x = 4. That is the second (and last) term in your quotient.

4x+15 - 4(x+2) =
4x+15 - 4x - 8 =
7
which is the remainder.

Your quotient is 3x+4, and your remainder is 7.

Answer 2

Dividing (3x^2 + 10x + 15) by (x + 2)
First of all notice that 3x^2 / x = 3x, so the answer will begin with 3x.
Multiply 3x and x + 2 to get (3x)(x + 2) = 3x^2 + 6x
Now subtract this from the original equation
3x^2 + 10x + 15
3x^2 + 6x
--------------------
4x + 15 <---- You get this

Now multiply (x + 2) by 4 to get 4x + 8
Now subtract this from (4x + 15)

4x + 15
4x + 8
-----------
7

So the answer is 3x + 4 with a remainder of 7.
Did you follow that?