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substance x
use the IR to identify the functional group present.
use NMR spectrum to determine the positions of the protonts

pic of x
http://img423.imageshack.us/img423/1807/compoundxrb5.jpg

substance y
use the IR spectrum to determine the functional group
use the IR to determine the reletive molar mass and significant fragments

pic of y
http://images6.theimagehosting.com/compound y.th.jpg

2006-10-11 09:11:15 · 2 answers · asked by The d 1 in Science & Mathematics Chemistry

sory, here is a working link to the second one
http://img254.imageshack.us/img254/2007/compoundybd7.jpg

2006-10-11 09:47:01 · update #1

2 answers

OK. For some reason the second image didn't come through, but I was able to view the first and here's what I came up with:

From the IR you can see a huge bulb inthe 3500 area. This is indicative of a hydroxy group, thus it is an alcohol.

The fragmenting of the mass-spec shows that it is a terminal alcohol; that is, the hydroxy group is on the end. This is known because your main peak is a 31, which is 16 + 15, which is equal to 1 O, 1 C and 3 H's. If it was a secondary -OH group you'd have at least 2 C's - one for the C joining to the O and one from peripheral branching. Also, your parent peak is 46, which is 16+2x12+6x1; thus there are only 2 C's anyway, so it has to be a terminal -OH group.

Your HNMR is throwing me off though. Are you sure that's the correct HNMR for this problem? Ethanol should only have 3 peaks total, assuming it detects the H on the OH.

2006-10-11 09:34:27 · answer #1 · answered by ohmneo 3 · 2 0

For compound X, you probably have ethanol:

compare the IR to this: http://en.wikipedia.org/wiki/Infrared_spectroscopy

the NMR to this:
http://home.clara.net/rod.beavon/ethanolNMR.gif

I can't get the link to your compound Y to work.

2006-10-11 16:45:07 · answer #2 · answered by Dave_Stark 7 · 0 0

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