The National Transportation Safety Board is testing the crash-worthiness of a new car. The 2300 kg vehicle, moving at 15 m/s, is allowed to collide with a bridge abutment, which stops it in 0.56 s. What is the magnitude of the average force that acts on the car during the impact? Can you explain your answers?
2006-10-11 08:52:02 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
You know from Newton's Laws that F = ma. Now i'll make a substitution: F = m(Δv/Δt). This makes sense because acceleration is the change in velocity. Now, let's use this formula to do the problem:
F = m(Δv/Δt)
F = m(vf - vo) / Δt
F = 2300(15) / 0.56
F = 61,607 N
2006-10-11 09:23:23 · answer #1 · answered by عبد الله (ドラゴン) 5 · 0⤊ 0⤋
Since the car goes from 15 m/s to 0 m/s in .56s, what is the average acceleration?
Knowing that and that the vehicle is 2300kg, what is the force involved?
2006-10-11 16:01:17 · answer #2 · answered by bag o' hot air 2 · 0⤊ 0⤋