Three points are on a coordinate plane: A(1, 5), B(-2, -4), and C(6, -4).?

Question

Can someone PLEASE Write an equation in point-slope form of the line with slope -1 that contains point C. And then 2. Write an equation in point-slope form of the line that contains points A an B.

Answer 1

Eq 1 = -1x -10
Eq 2 = 3x + 2, I think

Answer 2

1)
The equation for a line in the plane is
y=ax+b
the slope is defined by
dy/dx=a
hence you have
#) y=dy/dx*x+b
put the coordinate for A(1,5) and the given slope(-1) in the equation #) and calculate b

2) again y=ax+b
put the coordinate for B(-2,-4) in the equation, and do the same for C(6-,-4). Now you have to equations with the unknown a,b
solve the equations for a,b and you have the all your need to write the equation for the line through B,C

Answer 3

Point-slope form is

y-y0 = m(x-x0)

where (x0,y0) is any point on the line, and m is the slope, given by (y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are any two points on the line.

First problem: m = -1, so you have

y-y0 = -1(x-x0)

plug in the coordinates of C: x0=6, y0=-4 and then simplify to get the equation.

Second problem: let (x1,y1) = A, and (x2,y2) = B. Use these coordinates to compute the slope:

m = (-4 - 5) / (-2 - 1)

and then plug in the coordinates of either A or B for x0 and y0 to get the equation.

Answer 4

1.y+4=-1(x-6)
y=-x+2

2.y-5/-4-5=x-1/-2-1
-3(y-5)=-9(x-1)
y-5=3x-3
y=3x+2