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U will need a pen and paper for this

(13L to the power of 4 times M to the power of2 times N to the power of 2) divide by ( 26L squared times M to the power of 4 times N squared)


Good luck!!

2006-10-11 06:58:09 · 6 answers · asked by Adriaan 1 in Science & Mathematics Mathematics

6 answers

(13 L^4 M^2 N^2) / (26 L^2 M^4 N^2)

You can subtract exponents in the denominator from the corresponding exponents in the numerators. Thus, we have
* for L: 4 - 2 = 2
* for M: 2 - 4 = -2
* for N: 2 - 2 = 0

Since the exponent of N becomes zero, we can leave this factor out altogether (N^0 = 1 does not change the outcome). Also, dividing 13 by 26 gives 1/2. The answer is therefore

(1/2) L^2 M^(-2)

or, written as a single fraction with only positive exponents,

L^2 / (2 M^2)

2006-10-11 07:03:20 · answer #1 · answered by dutch_prof 4 · 0 0

I assume you mean

(13L^4 M^2 N^2) / (26L^2 M^4 N^2)

Use a^x / a^y = a^(x-y) and you get

(1/2)L^2 M^-2

2006-10-11 07:00:56 · answer #2 · answered by James L 5 · 0 0

hey adriaan what is the priority of your operators ?
for instance 13L to the power of 4 times M
is this 13 times L|^4 or (13L)^4

2006-10-11 07:50:07 · answer #3 · answered by gjmb1960 7 · 0 0

That's L squared times 3M times N squared divided by 2M squared.

2006-10-11 07:03:01 · answer #4 · answered by Roxy 2 · 0 0

I'm pretty sure the answer is 2LNegative squared times M

2006-10-11 07:09:53 · answer #5 · answered by Maria I 1 · 0 0

no good luck to you cuz its your homework

2006-10-11 07:01:33 · answer #6 · answered by Anonymous · 0 0

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