(6x^3+15x^2+2x+16) divided by (2x+5)?

Question

this one is like the last one...
This time it is supposed to be more
difficult?
To find the terms
Q(x) + R(x)/2x+5
where Q(x) is the quotient
and R(x) is the remainder

Ok smarty pants..
no, this is not an exam..
I already have this answer,
is this correct?

(3x^2+1) + (11)/2x+5

would this be correctly divided?

Answer 1

2x+5)6x^3+15x^2+2x+16(3x^2+1
6x^3 +15x^2
2x+16
2x+5
the answer
quotient=3x^2+1
remainder=11
in the conventional form
6x^3+15x^2+2x+16/(2x+5)
=3x^2+1+[11/(2x+5)]

Answer 2

Just take it step by step...

Step 1
=====
6 x^3 + 15 x^2 + 2 x + 16
(6 x^3 + ...) divided by (2 x + ...) gives 3 x^2.
3 x^2 times the divisor is 6 x^3 + 15 x^2; subtract this:

Step 2
=====
2 x + 16
(2 x + ...) divided by (2 x + ...) dives 1
1 times the divisor is 2 x + 5; subtract this:

Step 3
=====
11
This is the remainder.

Therefore,
Q(x) = 3 x^2 + 1
R(x) = 11

and the full quotient is 3 x^2 + 1 + 11/(2x+5)

Answer 3

Well Good Girl ;
we have this ;
(6x^3+15x^2+2x+16) ÷ (2x+5)

▪Step1
( 2x+5 )* ( 3x^2) = 6x^3 + 15x^2 ; {let R1 =3x^2}
6x^3 + 15x^2 + 2x + 16 - (6x^3 + 15x^2) =
6x^3 +15x^2 + 2x + 16 - 6x^3 - 15x^2= 2x + 16 {remainder}

▪Step 2
2x + 16 ÷ 2x+5
(2x+5 ) * (+1) = 2x + 5; { let R2 = +1 }
2x + 16 - ( 2x + 5 ) =
2x + 16 - 2x - 5 = 11{remainder}

▪Step 3
Sum R1 , R2 = quotient
Q (x) = R1 + R2
Q(x) = 3x^2 + 1
(6x^3+15x^2+2x+16) ÷ (2x+5) = R1 + R2
So;
(14y + 8y2 + y3 + 12) ÷ (6 + y) = 3x^2 + 1
And Remainder is : 11
Q(x) = 3x^2 + 1 { quotient}
R(x) = + 11 { remainder}

Good Luck Darling.

Answer 4

Ans= 3x^2 +1
Divider= 2x+5
Remainder= 11

Answer 5

I just answered this one

http://answers.yahoo.com/question/index;_ylt=AuR_5JfDWCg3aECOzd0vhk_zy6IX?qid=20061011101241AAxr9hc

Learn to do your homework. You can't ask Yahoo during an exam.

Answer 6

actually, this one is just as easy, since it too has already been answered.

and it has no remainder.