English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

simplify my answer...how is that possible, the dang thing is a mile long?

2006-10-11 05:03:16 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

I have this answer:
Is this as simplified as it can get?

answer= 30t^2-11xt-44t-28x^2+12x+16

2006-10-11 05:09:54 · update #1

10 answers

(6t-7x-4)(5t+4x-4)
= 30 t^2 + 24 tx - 24t - 35 tx -28 x^2 + 28 x - 20 t - 16 x + 16
= 30 t^2 - 28 x^2 - 11 tx - 44 t + 12 x + 16

2006-10-11 05:13:17 · answer #1 · answered by silverwhiskers 2 · 0 0

that's written as (6x + 4x - 6) - (4x - 7x + 4) on the grounds that multiplication is associative 3x2 = 3*2*x = 6x and 2x2 = 2*x*2 = 4x combine words: (10x - 6) - (-3x + 4) 10x - 6 + 3x - 4 10x + 3x - 6 - 4 13x - 10

2016-12-26 16:10:31 · answer #2 · answered by ? 3 · 0 0

=30t^2+24tx-24t
-35tx -28x-28x^2
-20t-16x +16
=30t^2-7tx-44t-44x-28x^2+16

2006-10-11 05:11:36 · answer #3 · answered by openpsychy 6 · 0 0

No you will have to simplify the like terms and shorten it

2006-10-11 05:12:32 · answer #4 · answered by william_mac_13 2 · 0 0

did you want the answer to the equation?....im not good at algebra but i come up with -144

2006-10-11 05:12:32 · answer #5 · answered by cookiesmom 7 · 0 0

Take both paranthesis and make each = 0
Solve for both x and t.

2006-10-11 05:28:03 · answer #6 · answered by yttap17 1 · 0 0

You've got it, although it might be arguable that it was simpler to start with!

2006-10-11 05:15:28 · answer #7 · answered by Sangmo 5 · 0 0

6t(5t+4x-4)-7x(5t+4x-4)-4(5t+4x-4)
=30t^2+24tx-24t-35tx-28x^2+28x-20t-16x+16
=30t^2-28x^2-11tx+12x-44t+16

2006-10-11 05:12:07 · answer #8 · answered by raj 7 · 0 0

(6t-7x-4)(5t+4x-4)
6t(5t+4x-4)-7x(5t+4x-4)-4(5t+4x-4)
30t^2+24tx-24t-35tx-28x^2+28x-20t-16x+16

30t^2-11tx-44t-28x^2+12x+16

2006-10-11 05:27:54 · answer #9 · answered by ain 1 · 0 0

what u wanna find....lol

2006-10-11 05:08:15 · answer #10 · answered by SAMUEL H 1 · 0 0

fedest.com, questions and answers